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problema fizica


ASZ12
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salut!am urmatoarea problema luata din variante de bac pe care nu am inteles-o:se dau 6 generatoare legate in serie de t.e.m. E si rezistenta interioara r legate cu un fir cu R=6,4 ohmiprin circuit circula un curent de I=1,8 A.daca la bornele generatorului format din cele sase generatoare in serie se inlocuieste firul cu R=6,4 ohmi cu unul de rezistenta neglijabila valoarea intensitatii curentului de scurt este Isc=21 A.imi cere rezistenta electrica a unui element.Stiu ca: Isc=E/r ;I=6E/R+6r ,dar cu toate acestea uitanduma la raspunsuri am vazut ca rezistenta unui element este r=0,1 ohm ..... cum ???multumesc !!

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